Trig Proof Help

[bdub91284]

Need to prove...

[sinx]/[(cosx)^2-(sinx)^2] = [tanx]/[1-(tanx)^2]

I'm assuming the only identities you might need are...

(sinx)^2+(cosx)^2=1
tanx=sinx/cosx
and maybe 1+(tanx)^2=(secx)^2 where secx=1/cosx

Help,
Brandon

[jado818]

I plugged that equation into my graphing calculator and it doesn't look like they equal each other.

Im using a TI-89 calculator in radians mode.

maybe you got a sign switched around somewhere man...

Jack