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conics
01-16-2007, 08:40 PM
A basketball team has won 50 games of 75 played. The team still has 45 games to play. How many of the remaining games must the team win in order to win 60% of all games played during the season?

HallsofIvy
01-17-2007, 01:15 PM
"Percentage won" is based on games won divided by total number of games played. If you have already played 75 games ane there are 45 games remaining then there are 75+ 45= 120 games in the season. Call the number of games you need to win of the remaining games "x". If you win "x" more games, then, since you have already won 50 games, at the end of the season you will have won x+ 50 games and so "games won divided by games played" will be (x+50)/120. 60% corresponds to the fraction 0.6 so you must have (x+ 50)/120= 0.6. Can you solve that equation for x?

conics
01-17-2007, 08:48 PM
Yes, I can solve the equation for x.

Thanks!