View Full Version : Gravity Rooms.....
10-08-2005, 02:46 PM
Hey everyone, Im brand new here and just wanted to say hello !
Ok, I have a question and if anyone can reply with anything to do with the subject I will be greatfull!
Does there exsist (or is it possible to have) a room/machine which enables the force of gravity to be increased??? Basically the room would be the complete opposite to ZERO gravity (what astronaughts experience).
Increasing the gravity would add extra strain to the the human body as body weight would increase.
10-08-2005, 05:30 PM
Centripetal force would make one feel like gravity is increasing, but I guess that doesn't really increase gravity. :)
11-08-2005, 12:33 PM
I think i have heard of them but dont remember much about them
They are also used for training purposes
Tried to find on the net about it but could not get much information on it
03-08-2008, 09:53 PM
I tried to look up the same thing but i could not find it either dose ANY ONE know about them or how to make them :confused:
03-10-2008, 08:18 AM
I tried to look up the same thing but i could not find it either dose ANY ONE know about them or how to make them :confused:Try riding a rocket into space.
05-20-2008, 05:05 AM
06-29-2008, 11:55 PM
acceleration including centrifugal acceleration, can "mimic" gravitational force but there is no way to actually change the graviational force on a body.
(And, just out of curiosity, what does this have to do with "computers"?)
01-14-2010, 11:47 AM
Heavy Gravity Rooms were special exercise rooms on the Executive Level of the first Death Star where an user could change the level of gravity in the room. Higher settings of gravity meant the user could burn more energy, lose more weight, and build more muscle.
07-30-2010, 03:55 AM
I'm surprised no one has really given a good answer to this question yet. You could make a room with artificially increased gravity the same way they create artificial gravity in space.
By using a spinning room you would feel an extra centripetal force parrallel to the ground towards the walls of the room and when combined with the force of gravity the overall force is in a diagonal down/outward force. F = mv^2/r, or F=mrw^2 where w is the angular velocity. The second equation is more useful when talking about a room since the angular velocity is the same no matter where in the room you are where if you use the first equation you have to deal with a changing velocity v.
In order to always feel like you are standing on flat ground the floor would have to be concave up, nearly parallel with the Earth in the center, becoming more inclined near the walls with the floor normal to the direction of the combined gravitational and centripetal forces.
g is 9.81 m/s^2, or 32.2 ft/s^2, so in order to have a room with the effect of 2g at the outward edge of the room you need a a value of16.99m/s^2 or 55.77 ft/s^2 (Pythagorean theorem) for rw^2= v^2/r at the edge of the room. This gives a force vector going into the ground with an angle to the horizon of 30 degrees, so you would need the floor to have a 60 degree incline at this point.
One way to achieve this would be to have multiple motors around the edges of the circular room with a radius of 24.11 ft,giving the edges a speed of 25 miles/hour, or a room of radius 96.43 ft and and edge speed of 50 miles/hour. The entrance to the room should be in the center where there is no centrepital force. The smaller room would revolve once every 4.13 seconds and the larger room would revolve every 8.26 seconds, so the large the room with a 2g force at the outer edge the easer the room would be to enter while moving, but harder to keep moving, and start moving.
The floor can be modeled by a simple parabola rotated 360 degrees. since the slope is given by the derivative you could match the radius and 60 degree incline to the second derivative of the standard parabola (slope of 0.5774), so
a = .011974
y = .011974 x^2 giving the floor of the outer edge of the building a height of 6.96 ft
.5774 = (2)a(96.43)
a = .002994
y = .002994 x^2 giving the floor of the outer edge of the building a height of 27.84 feet.
I would calculate the amount of energy needed to get these buildings rotated, and possibly how much energy to keep them rotating, but I don't know how much the buildings tend to weigh, and these would undoubtedly be more massive than regular buildings, and I'm not sure how efficiently you could keep them rotating, with friction and other lost energy. Wikipedia has some stats for how many g's different circumstances give, if you search g-force, but if you were just trying to make lets say a gym with more gravity to train 2gs should be plenty since a 180lb man would feel 360 lbs of force, twice his weight.
08-16-2010, 08:13 PM
Is there such a thing as zero gravity rooms?
08-25-2010, 03:51 PM
I found this on the internet:
"No. There isn't such a thing on Earth. The closest thing we have, well NASA has, is the NBL, or the Neutral Buoyancy Lab. It is a giant pool, at Johnson Space Center, in Houston, Tx where astronauts train for EVA's, or Extra Vehicular Activities. They are weighted so that they "hover" in one spot, and don't sink or float."
09-15-2010, 09:11 AM
They can take people by an aircraft to an higher altitude and drop the plane to a certain lower height.during the calculated fall of the aircraft persons inside the aircraft feel zero gravity.
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